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数学
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方程组2x²+5y²-4x+y-6=0,x²+2y²-2x+y-3=0
人气:187 ℃ 时间:2020-03-25 20:33:50
解答
①-②×2得,y²-y=0
∴y1=0 y2=1
把y=0代入②得,x²-2x-3=0
∴x1=3,x2=-1
把y=1代入②得,x²-2x=0
∴x3=0,x4=2
∴方程组的解是
x=3 x=-1 x=0 x=2
y=0 y=0 y=1 y=1
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