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sinxcosx+cosx^2-2 化简
人气:306 ℃ 时间:2020-10-01 21:07:14
解答
sinxcosx+cosx^2-2
=(1/2)*2sinxcosx+(1/2)*[2*(cosx)^2-1]-(3/2)
=(1/2)sin2x+(1/2)cos2x-(3/2)
=(√2/2)sin(2x+π/4)-(3/2)
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