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因式分解:(x-1)(x-2)(x-3)(x-4)-48用8年级的方法
人气:220 ℃ 时间:2020-06-13 20:47:28
解答
(x-1)(x-2)(x-3)(x-4)-48 =[(x-1)(x-4)][(x-2)(x-3)] =(x-5x+4)(x-5x+6)-48 =(x-5x)+10(x-5x)+24-48 =(x-5x)+10(x-5x)-24 =(x-5x+12)(x-5x-2)
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