有关溶液稀释和浓缩的计算
1.配制800mL63%的硝酸( 密度为1.4g / cm3 ),需浓度为96%的硝酸( 密度为1.5g / cm3 )多少mL和水多少mL?
2.20%的蔗糖(C12H22O11)溶液342克稀释到1升,其物质的量浓度将是多少?
3.将10毫升2 mol/L的硫酸溶液加水稀释到0.5mol/L,其体积为多少毫升?
4.配制500mL1 mol/L的H2SO4溶液,需要密度为1.836g/mL的浓硫酸(98%硫酸)多少毫升?
人气:454 ℃ 时间:2020-06-16 21:29:45
解答
1.800*63%*1.4=x*1.5*96%,x=490(mL)
水=800*1.4-490*1.5=945(mL)
2.342*20%/342*1=0.2(mol/L)
3.10*2=x*0.5,x=40(mL)
4.0.500*1*98=x*1.836*98%,x=27.23(mL)
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