如图,AB,CD,EF相交于点O,EF⊥AB,OG平分∠COF,OH平分∠DOG,若∠AOC:∠COG=4:7,求∠DOF、∠DOH的大小.
人气：362 ℃ 时间：2020-04-06 18:10:55
解答
我省掉标角符号好吧
2COG=COF=AOC+90=2*7/4AOC=7/2AOC
AOC=36
DOF=90-BOD=90-AOC=54;
DOH=1/2DOG=1/2(180-COG)=58.5
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