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tanπ/12-cotπ/12
人气:459 ℃ 时间:2020-06-16 19:39:25
解答
=sinπ/12/cosπ/12-cosπ/12/sinπ/12
=(sin²π/12-cos²π/12)/(sinπ/12cosπ/12)
=-cos(2*π/12)/[1/2*sin(2*π/12)]
=-cosπ/6/(1/2*sinπ/6)
=-2√3
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