当然是了.因为
n(n+3)-(n-4)(n-5)=12n-20=4(3n-5)需要写∵和∴的这道题∵n(n+3)-(n-4)(n-5)=12n-20=4(3n-5)
∴对于任意自然数n,代数式n(n+3)-(n-4)(n-5)的值都能被4整除