∫e^x·sin2xdx=e^x·sin2x-2∫e^xcos2xdx=e^x·sin2x-2[e^x·cos2x+2∫e^x·sin2x]dx=e^x·sin2x-2e^x·cos2x-4∫e^x·sin2x dx得5∫e^x·sin2xdx=e^x·sin2x-2e^x·cos2x+C1故∫e^x·sin2xdx=1/5·e^x·(sin2x-2co...