令f(x)=[(m+3)x-1](x+10)=0,则：x=1/(m+3)或x=-10比较：若1/(m+3)＞-10,既m≤-31/10时：x∈(1/(m+3),＋∞)∪(－∞,－10)若1/(m+3)＜-10,既-31/10＜m≤3时：x∈(－10,＋∞)∪(－∞,1/(m+3))若1/(m+3)＝-10,既m＝-31/1...