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三角函数 化简
(1) 1/(sin 10°)-√3/(cos 10°);
(2) sin 40°(tan 10°-√3).
人气:425 ℃ 时间:2020-06-12 16:02:58
解答
(1) 1/(sin 10°)-√3/(cos 10°)
=(cos 10°-√3sin 10°)/sin 10°*cos 10°
=2(1/2cos 10°-√3/2sin 10°)/sin 10°*cos 10°
=2sin (30°-10°)/sin 10°*cos 10°
=2sin 10°*cos 10°/sin 10°*cos 10°
=2
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