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sin(kπ-α)*cos〔(k-1)π-α〕/sin〔(k+1)π+α〕*cos(kπ+α) ,k属于Z
人气:293 ℃ 时间:2020-03-23 08:09:47
解答
当k为偶数时
sin(kπ-α)*cos〔(k-1)π-α〕/[sin〔(k+1)π+α〕*cos(kπ+α) ]
=-sina*(-cosa)/[-sina*cosa]
=-1
当k为奇数时
sin(kπ-α)*cos〔(k-1)π-α〕/[sin〔(k+1)π+α〕*cos(kπ+α) ]
=sina*(cosa)/[sina*-cosa]
=-1
综上所述,sin(kπ-α)*cos〔(k-1)π-α〕/[sin〔(k+1)π+α〕*cos(kπ+α) ]=-1
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