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已知x=2013,y=2014,求(x+y)(x^2+y^2)/x^4-y^4
人气:467 ℃ 时间:2020-02-06 00:44:16
解答
由(x+y)(x^2+y^2)/x^4-y^4
=(x+y)(x^2+y^2)/(x^2+y^2)*(x^2-y^2)
=(x+y)/(x^2-y^2)
=(x+y)/(x-y)(x+y)
=1/(x-y)
=1/(2013-2014)
=-1
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