解;先求偏导数:f(x,y)=(x+y^2+2y)e^(2x)fx(x,y)=e^(2x)+2(x+y^2+2y)e^(2x)fy(x,y)=(2y+2)e^(2x)令fx(x,y)=0,fy(x,y)=01+2(x+y^2+2y)=02y+2=0y=-1x=1/2fxx(x,y)=[e^(2x)(1+2x+2y^2+4y)]x=2e^(2x)+2(1+2x+2y^2+4y)e^(2...