解方程组:xy/(x+y)=6,xy/(9x+6y)=1
人气:362 ℃ 时间:2019-12-21 13:27:52
解答
【方法一】xy/(x+y)=6,则xy=6x+6y
xy/(9x+6y)=1,则xy=9x+6y
故6x+6y=9x+6y,得x=0,于是6x+6y=0,y=0
显然这个不是方程组的解,所以该方程组无解
【方法二】xy/(x+y)=6,xy=6(x+y),则可设x+y=1,xy=6
x、y可看成方程x^2-x+6=0的解,而Δ=1-24=-23若方程组为xy/(x+y)=6,xy/(9x+4y)=16x+6y=9x+4y,x=2y/3带入xy=6x+6y2y^2/3=6*2y/3+6y,y^2/3=5y,显然y不等于0,所以y=15带入xy=6x+6y于是15y=6x+6*15,x=10故该方程组解为x=10,y=15
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