|ab-2|+(b-1)的平方=0,求 1/ab +1/(a+1)(b+1) +1/a+2)(b+2)+ .+1/(a+ 2010)(b+2010)的值
|ab-2|+(b-1)的平方=0,求 1/ab +1/(a+1)(b+1) +1/a+2)(b+2)+ .+1/(a+ 2010)(b+2010)的值
人气:330 ℃ 时间:2020-05-12 06:01:38
解答
|ab-2| (b-1)的平方=0 ab-2=0,b=1 a=2,b=1 1/ab 1/(a b)(b 1) 1/(a 2)(2 b) ```````` 1/(a 2008)(b 2008) =1/1*2 1/2*3 1/3*41/2008*2009 =(1-1/2) (1/2-1/3) (1/3-1/4) . (1/2008-1/2009) =1-1/20
推荐
猜你喜欢