若/AB-2/+(A-2)平方=0,求1/AB+1/(A+1)(B+1)+1/(A+2)(B+2)+……+1/(A+2010)(B+2010)的值.
人气:276 ℃ 时间:2020-05-17 14:09:22
解答
ab-2=0a-2=0∴a=2b=11/AB+1/(A+1)(B+1)+1/(A+2)(B+2)+……+1/(A+2010)(B+2010)=1/1×2+1/2×3+1/3×4+1/4×5+……+1/2011×2012=1-1/2+1/2-1/3+1/3-1/4+1/4-……-1/2011+1/2011-1/2012=1-1/2012=2011/20...
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