计算定积分:∫(xe^x+1)dx,(区间0到1 )
∫[0,1](xe^x+1)dx
=∫[0,1](xe^x)dx+x[0,1]
=∫[0,1]xde^x+1
=xe^x[0,1]-∫[0,1]e^xdx+1
=e-1-e^x[0,1]
=0