> 其他 >
等差数列{an},{bn}的前n项和分别为Sn,Tn,若
Sn
Tn
=
2n
3n+1
,则
an
bn
=______.
人气:380 ℃ 时间:2020-06-14 15:17:40
解答
Sn
Tn
=
2n
3n+1

S2n−1
T2n−1
2(2n−1)
3(2n−1)+1
4n−2
6n−2
2n−1
3n−1

an
bn
(2n−1)an
(2n−1)bn
S2n−1
T2n−1
2n−1
3n−1

故答案为:
2n−1
3n−1
推荐
猜你喜欢
© 2026 79432.Com All Rights Reserved.
电脑版|手机版