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(-4x^2y)^3÷(-8x^3y)÷(-4x^2y^2)要过程 (x^2y)*(1/2x^3y^4)÷(1/4x^4y^3)要过程
人气:287 ℃ 时间:2020-09-15 20:15:02
解答
(-4x^2y)^3÷(-8x^3y)÷(-4x^2y^2)
=-64x^6y^3÷(-8x^3y)÷(-4x^2y^2)
=8x^3y^2÷(-4x^2y^2)
=-2x
(x^2y)*(1/2x^3y^4)÷(1/4x^4y^3)
=1/2x^5y^5÷(1/4x^4y^3)
=2xy²7x^3y^2÷[(-7x^5y^3)÷(-1/3x^3y^2)]要过程谢谢3x^m+1y^n+1÷(-1/3x^my^n-1)*(1/9y)^2要过程谢谢需要采纳吗?7x^3y^2÷[(-7x^5y^3)÷(-1/3x^3y^2)]=7x^3y^2÷(7/3x²y)=3xy3x^m+1y^n+1÷(-1/3x^my^n-1)*(1/9y)^2=-9xy²*(1/9y^2)=-xy^4
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