求数列2x^2,3x^3,4X^4,...,nX^n,...的前n项和
过程
人气:294 ℃ 时间:2020-04-23 11:42:25
解答
令和为N,当x=1时,N=2+3+……+n=(n+3)n/2;
当x≠1时,xN=2x^3+……+nx^(n+1)
(x-1)N
=nx^(n+1)-(x^3+x^4+……+x^n)-2x^2
=nx^(n+1)-x^3(1-n^(n-2))/(1-x)-2x^2
N=(nx^(n+1)-x^3(1-n^(n-2))/(1-x)-2x^2)/(x-1)
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