求函数的定义域f(x)=根号下(2x-1)/x-3
人气:286 ℃ 时间:2020-03-23 10:06:26
解答
(2x-1)/(x-3)≥0
2+5/(x-3)≥0
5/(x-3)≥-2
x-3>0或x-3≤-5/2
x>3或x≤1/2(2x-1)/(x-3)≥0怎么变成2+5/(x-3)≥0的?(2x-1)/(x-3)=[2(x-3)+5]/(x-3)=2+5/(x-3)≥0 其实(2x-1)/(x-3)≥0等价于(2x-1)(x-3)≥0且(x-3)≠0
推荐
猜你喜欢
- 从1、2、3、4、5、6、7、8、9中任意选出三个数,使它们的和为奇数,则共有几种不同的选法.
- 一种商品先提价百分之15又降价百分之20现价相当于原价的百分之几
- 火柴棒摆金鱼:一条金鱼八只火柴棒,2条金鱼是14条火柴棒,3条20只,小明用32跟摆了N条 求金鱼条数N
- a youna young man from a wealthy family was about to graduate from high school .it was the
- the wood was so __ that when they pressed ,it broke
- 0-9 (10个数)三个数排列一组,能排几组,公式=?
- 用4,6,9,0和小数点组成小数,哪些小数四舍五入后近似数为4
- 化工原理实验之流体流动阻力的测定