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若x=2007,y=2008,则(x+y)*(x的四次-y的四次)分之(x的平方+y的平方)
人气:130 ℃ 时间:2020-06-09 16:12:42
解答
先进行简化,再代入即可:
原式=(x+y)*(x*x+y*y)/(x*x*x*x-y*y*y*y)
=(x+y)*(x*x+y*y)/((x*x+y*y)(x*x-y*y))
=(x+y)/(x*x-y*y)
=(x+y)/((x+y)*(x-y))
=1/(x-y)
=1/(2007-2008)
=-1
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