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在实数范围内因式分解x^2-4xy+3y^2-4x+10y+3和x^2+xy-2y^2+2x+7y-3
人气:421 ℃ 时间:2019-08-18 06:19:01
解答
x^2-4xy+3y^2-4x+10y+3
=(x-y)(x-3y)-4x+10y+3
=(x-y-3)(x-3y-1)
x^2+xy-2y^2+2x+7y-3
=(x-y)(x+2y)+2x+7y-3
=(x-y+3)(x+2y-1)(x-y)(x-3y)-4x+10y+3到(x-y-3)(x-3y-1),(x-y)(x+2y)+2x+7y-3到(x-y+3)(x+2y-1)怎么来的十字相乘法x-y -3 x-y3 ╳ ╳x-3y -1 x+2y-1(x-y-3)(x-3y-1)(x-y+3)(x+2y-1)再详细些,列个式子,我数学比较差十字相乘法x-y -3 x-y3 ╳ ╳x-3y -1x+2y-1(x-y-3)(x-3y-1)(x-y+3)(x+2y-1)这就是列的式子
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