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证明 0.0999
人气:409 ℃ 时间:2020-04-11 05:39:57
解答
[1/(10x10)+1/(11x11)+1/(12x12)+.+1(1000x1000)]>[1/(10x11)+1/(11x12)+1/(12x13)+.+1(1000x1001)]
1/(10x11)+1/(11x12)+1/(12x13)+.+1(1000x1001)
=(1/10)-(1/11)+(1/11)-(1/12)+.+(1/1000)-(1/1001)
=(1/10)-(1/1001)=0.099
[1/(10x10)+1/(11x11)+1/(12x12)+.+1(1000x1000)]
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