证明0.0999<1/10"+1/11"+1/12"+.+1/1000"<0.111
证明:0.0999<[1/(10x10)+1/(11x11)+1/(12x12)+.....+1(1000x1000)]<0.111
人气:118 ℃ 时间:2020-04-13 21:13:56
解答
[1/(10x10)+1/(11x11)+1/(12x12)+.+1(1000x1000)]>[1/(10x11)+1/(11x12)+1/(12x13)+.+1(1000x1001)]=(1/10)-(1/11)+(1/11)-(1/12)+.+(1/1000)-(1/1001)=(1/10)-(1/1001)=0.099[1/(10x10)+1/(11x11)+1/(12x12)+.+1(10...
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