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圆的方程x²+y²-2(m+3)x+2(1-4m²)y+16m^4+9=0 求实数a的取值范围
人气:385 ℃ 时间:2019-10-11 02:41:45
解答
x²+y²-2(m+3)x+2(1-4m²)y+16m^4+9=0
(x-m-3)²+(y+1-4m²)²=m²+6m+9+1-8m²+16m^4-16m^4-9
(x-m-3)²+(y+1-4m²)²=-7m²+6m+1
r²=-7m²+6m+1>0
7m²-6m-1<0
(7m+1)(m-1)<0
-1/7<m<1
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