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分解因式:(p²+q²)²-4p²q²
人气:334 ℃ 时间:2020-02-03 04:49:28
解答
(p²+q²)²-4p²q²=(p²+q²)-(2pq)²=[(p²+q²)+2pq][(p²+q²)-2pq]=(p²+2pq+q²)(p²+-2pq+q²)=(p+q)²(p-q)²很高兴为您解答,【...
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