以AB整体为研究对象,整体所受合力F合=5mg+3mg+qE
AB整体的加速度a=
8mg+qE |
8m |
qE |
8m |
C只受重力,故加速度为g
对A运用牛顿第二定律
A球所受合力FA=5mg+T
A 球产生的加速度aA=g+
qE |
8m |
根据牛顿第二定律有:FA=maA
代入得5mg+T=5m(g+
qE |
8m |
整理得:T=
5qE |
8m |
故答案为:g+
qE |
8m |
qE |
8m |
5qE |
8m |
8mg+qE |
8m |
qE |
8m |
qE |
8m |
qE |
8m |
5qE |
8m |
qE |
8m |
qE |
8m |
5qE |
8m |