> 其他 >
1.若0若x>0,y>0,则3[(x^2/y^2)+(y^2/x^2)]-8[(x/y)+(y/x)]+10的最小值为?
人气:317 ℃ 时间:2020-04-11 00:52:59
解答
1)tan(x-y)=(tanx-tany)/(1+tanxtany)=2tany/(1+3tan^2y)=2/(1/tany+3tany)≤2/2√(1/tany*3tany)=1/√3=√3/3=tanπ/6x-y的最大值为:π/62)(x^2/y^2)+(y^2/x^2)=(x/y+y/x)^2-23[(x^2/y^2)+(y^2/x^2)]-8[(x/y...
推荐
猜你喜欢
© 2026 79432.Com All Rights Reserved.
电脑版|手机版