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如何因式分解 xyz(x^3+y^3+z^3)-x^3y^3-y^3z^3-z^3x^3
人气:341 ℃ 时间:2019-09-09 17:48:10
解答
xyz(x³+y³+z³)-x³y³-y³z³-z³x³
=x^4yz+xyz(y³+z³)-y³z³-x³(y³+z³)
=yz(x^4-y²z²)+x(yz-x²)(y³+z³)
=yz(x²+yz)(x²-yz)-x(x²-yz)(y³+z³)
=(x²-yz)(x²yz+y²z²-xy³-xz³)
=(x²-yz)[y²(z²-xy)-xz(z²-xy)]
=(x²-yz)(y²-xz)(z²-xy)
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