若sin(x+y)=1/2,sin(x-y)=1/3,则tanx/tany等于?
人气:196 ℃ 时间:2019-12-11 09:43:58
解答
sin(x+y)=sinxcosy+cosxsiny=1/2,sin(x-y)=sinxcosy-cosxsiny=1/3,两式作商得(sinxcosy+cosxsiny)/(sinxcosy-cosxsiny)=3/2,分子分母同时除以cosxcosy得(tanx+tany)/(tanx-tany)=3/2,所以2tanx+2tany=3tanx-3tan...
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