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求证tanx+tany/tanx-tany=sin(x+y)/sin(x-y)(详细步骤)
人气:425 ℃ 时间:2019-12-24 08:15:24
解答
(tanx+tany(/(tanx-tany)
分子分母同乘以cosxcosy:
=(sinxcosy+cosxsiny)/(sinxcosy-cosxsiny)
=sin(x+y)/sin(x-y)
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