f(x)=(sin²x+cos²x)+√3sinxcosx+cos²x=1+√3/2*sin2x+(1+cos2x)/2=√3/2sin2x+1/2*cos2x+3/2=sin2xcosπ/6+cos2xsinπ/6+3/2=sin(2x+π/6)+3/2=sin[2(x+π/12)]+3/2所以向左移π/12单位然后把横坐标...