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已知x²-4x+4与|y-1|互为相反数,则式子(y/x - x/y)÷(x+y)的值等于?
人气:311 ℃ 时间:2020-03-25 16:11:34
解答
x²-4x+4+|y-1|=0
(x-2)^2+|y-1|=0
x-2=0 x=2
y-1=0 y=1
(y/x - x/y)÷(x+y)
=(y^2-x^2)/(xy)*[1/(x+y)]
=(x+y)(y-x)/(xy)*[1/(x+y)]
=(y-x)/(xy)
=(1-2)/2
=-1/2
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