[(x-2)^3-(x-1)^2+1]/(x-2)=[(x-2)^3-(x^2-2x+1)+1]/(x-2)=[(x-2)^3-(x^2-2x)]/(x-2)=[(x-2)^3-x(x-2)]/(x-2)=(x-2)^2-x=(x^2-4x+4)-x=x^2-5x+4∵x^2-5x-2007=0∴x^2-5x=2007∴[(x-2)^3-(x-1)^2+1]/(x-2)=x^2-5x+4=2...