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(x-y)^5(y-x)^5+[(x-y)^5]的2次;
人气:198 ℃ 时间:2020-10-01 21:16:50
解答
(x-y)^5(y-x)^5+[(x-y)^5]的2次
= -(x-y)^5(x-y)^5+[(x-y)^5]^2
= -(x-y)^10+(x-y)^10
= 0
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