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(1)一直b1=27,b6=1/9,则S6=?(2)已知b1=3/2,q=-1/2,Sn=33/32,则n=?(3)若{an}是等比数列,且S5=31,S6-S1=62,则数列的公比是?(4)等比数列1,1,1......的前100项和S100=?
人气:421 ℃ 时间:2020-06-02 00:34:00
解答
b6=b1q^5
1/9=27*q^5
(1/3)^5=q^5
q=1/3
s6=b1(1-q^5)/(1-q)
=1/9*[1-(1/3)^5]/(1-1/3)
=2/3*[1-(1/3)^5]
=2/3*242/243
=484/729
sn=b1(1-q^n)/(1-q)
33/32=3/2*[1-(-1/2)^n]/(1+1/2)
33/32=1-(-1/2)^n
1/32=-(-1/2)^n
-1/32=(-1/2)^n
(-1/2)^5=(-1/2)^n
n=5
S5=31,
S6-S1=62
b1(1-q^6)/(1-q)-b1(1-q)/(1-q)=62
[b1(1-q^6)-b1(1-q)/(1-q)=62
b1[1-q^6)-1+q]/(1-q)=62
b1[q-q^6)+)/(1-q)]=62
b1q(1-q^5)/(1-q)=62
qs5=62
31q=62
q=2
s100=100
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