令t=x-π/3,则当x->π/3时,t->0∴原式=lim(t->0){[1-2cos(t+π/3)]/sint}=lim(t->0){[1-2(cost/2-√3sint/2)]/sint}=lim(t->0)[(1-cost+√3sint)/sint]=lim(t->0)[(1-cost)/sint+√3]=√3+l...