根号[(3/sin20')-(1/cos20')],
人气：277 ℃ 时间：2020-01-09 05:12:37
解答
√3/sin20°-1/cos20°
=(√3cos20°-sin20°)/sin20°cos20°
=2(sin60°cos20°-cos60°sin20°)/sin20°cos20°
=2sin40°/0.5sin40°=4.
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