若△abc的三边长分别为4,5,7,则△abc的面积是?内切圆半径?
如题
人气:402 ℃ 时间:2019-12-09 08:18:59
解答
△ABC中:a,b,c分别为三边三角形的面积S可由以下公式求得:
s=√[p(p-a)(p-b)(p-c)] p=(a+b+c)/2=8
=√[8(8-4)(8-5)(8-7)]
=√(8x4x3)
=4√6
△ABC中:a,b,c分别为三边,S为三角形面积,则内切圆半径r=2S/(a+b+c)
r=2x4√6/(a+b+c)
=8√6/16
=√6/2
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