> 数学 >
1.1-x+4分之x^2
2.(x-y)^2-4(x-y-1)
3.已知m+n=3,mn=三分之二,求m^2+(n-mn)^2+2m(n-mn)的值
人气:369 ℃ 时间:2020-10-02 04:18:15
解答
1.1-x+4分之x^2
=(1-x/2)^2
2.(x-y)^2-4(x-y-1)
=(x-y)^2-4(x-y)+4
=(x-y-2)^2
m^2+(n-mn)^2+2m(n-mn)
=(m+n-mn)^2
=(3-2/3)^2
=(7/3)^2
=49/9
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