先化简,再求值:[(x^2-6x)/(x+2)+2]/(x^2-4)/(x^2+4x+4),其中x=2+根号3
快的还加
人气:336 ℃ 时间:2019-11-25 16:03:57
解答
[(x^2-6x)/(x+2)+2]/[(x^2-4)/(x^2+4x+4)]
=[(x^2-6x+2x+4)/(x+2)]/[(x^2-4)/(x+2)^2]
=[(x^2-4x+4)/(x+2)]/[(x-2)(x+2)/(x+2)^2]
=[(x-2)^2/(x+2)]/[(x-2)/(x+2)]
=(x-2)^2/(x+2)*(x+2)/(x-2)
=x-2
=2+根号3-2
=根号3
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