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(3/4x^3y^3z^3-1/3x^2y^2z+1/2xy)/1/12xy
人气:353 ℃ 时间:2020-03-27 06:50:15
解答
原式=(3/4x^3y^3z^3)× 12/(xy) -(1/3x^2y^2z)× 12/(xy)+(1/2xy)× 12/(xy)
=9x²y²z³ - 4xyz + 6
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