x→0+
lim |sinx| =lim sinx =0 =sin 0
x→0-
lim sinx = lim -sinx =0 =sin 0
左右都连续.所以连续
x→0+
lim (|sinx|-|sin0)|/(x-0) =lim sinx/x =1
x→0-
lim (|sinx|-|sin0)|/(x-0) = lim -sinx/x =-1
左右导数不等,所以不可导