(x²+xy+y²)²-4xy(x²+y²)分解因式_数学解答

(x²+xy+y²)²-4xy(x²+y²)分解因式

人气：312 ℃　时间：2020-02-03 21:11:03

解答

(x²+xy+y²)²-4xy(x²+y²)＝(x²+xy+y²)²-4xy(x²+y²)=[(x^2+y^2)+xy]^2-4xy(x²+y²)=(x^2+y^2)^2+2xy(x^2+y^2)+x^2y^2-4xy(x²+y²)=(x^2+y^2)^2-...