y=sin(2x+π/4)的图像怎么画
人气:433 ℃ 时间:2020-01-30 17:16:53
解答
用五点法
就是y=0,y=1,y=-1
y=0,则2x+π/4=-π,x=-5π/8
2x+π/4=0,x=-π/8
2x+π/4=π,x=3π/8
y=1,2x+π/4=π/2,x=π/8
y=-1,2x+π/4=-π/2,x=-3π/8
所以五点是
(-5π/8,0),(-3π/8,-1),(-π/8,0),(π/8,1),(3π/8,0)
然后描出来就可以了
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