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高一三角函数化简题
(1+sinθ+cosθ)×(sin(θ/2)-cos(θ/2))
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根号下(2+2cosθ)
由于等级不够,不能上图所以大家体谅下哈.中间是分数线
人气:493 ℃ 时间:2020-06-13 09:28:14
解答
1+sinθ+cosθ=sin²(θ/2)+cos²(θ/2)+2sin(θ/2)cos(θ/2)+cos²(θ/2)-sin(θ/2)=[sin(θ/2)+cos(θ/2)]²+[sin(θ/2)+cos(θ/2)][cos(θ/2)-sin(θ/2)]=[sin(θ/2)+cos(θ/2)][sin(θ/2)+cos(...
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