a+b-2√(a-1)-4√(b-2)=3√(c-3)-1/2c-5=>a+b-2√(a-1)-4√(b-2)+1/2c-3√(c-3)+5=0=>[a-1-2√(a-1)+1]+[b-2-4√(b-2)+4]+1/2[c-3-6√(c-3)+9]=0 =>(√(a-1)-1)^2+(√(b-2)-2)^2+1/2(√(c-3)-3]^2=0 =>√(a-1)-1=0...