∵一元二次方程（m-2）²x²+(2m-1)x+1=0有两个不相等的实数根∴△=（2m-1)²-4*1*(m-2)²＞04m²-4m+1-4*(m²-4m+4)＞04m²-4m+1-4m²+16m-16＞0 1...