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数学
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x(x^2-1)+2x^2 *(x+1)-3x*(2x-5)=x(3x^2-4x)-28
人气:297 ℃ 时间:2019-11-18 02:56:27
解答
x(x^2-1)+2x^2 *(x+1)-3x*(2x-5)=x(3x^2-4x)-28;
x^3-x+2x^3+2x^2-6x^2+15x=3x^3-4x^2-28;
14x=-28.
x= -2.
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